In boot camp, a cadet must use a rope swing to cross an obstacle without falling into the water hazard below. Unfortunately, they miss the platform on the other side and swing back to where they started. If it takes the cadet 3.5 seconds to swing from one side of the obstacle to the other and back, how Lind is the rope swing? Use the formula: T= 2 pi square root over L/9.8

3.04m

Step-by-step explanation:

Time taken to swing the rope = 3.5s

Length of the rope = L

T = 2π√(L / 9.8)

3.5 = 2π√(L / 9.8)

take the square of both sides

(3.5)² =[2π√(L/9.8)]²

12.25 = 39.48 × (L / 9.8)

12.25 = 39.48L / 9.8

39.48L = 12.25 × 9.8

39.48L = 120.05

L = 120.05 / 39.48

L = 3.04m

The length of the rope is 3.04m

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

she gotta workk that a 2

step-by-step explanation: