What is the first step in solving a quadratic equation of the form given below?
(ax + b)^2 = 0
A. Take the square root of both sides
B. Factor out a common factor
C. Divide both sides by c
D. Use the zero product rule

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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step-by-step explanation: i dont

2

step-by-step explanation: