Find the product of 5jk(k – 2j)

5jk²-10j²k

Step-by-step explanation:

We simply distribute the 5jk to both terms.

5jk(k) = 5jk²

5jk(-2j) = -10j²k

And then we write them together: 5jk²-10j²k

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an advantage of the standard deviation is that it increases as the dispersion of the data increases. e. the interquartile range is preferred when the data are not skewed or no have outliers. an advantage of the standard deviation is that it uses all the observations in its computation.