In ΔABC, the measure of ∠C=90°, the measure of ∠A=47°, and BC = 3.5 feet. Find the length of AB to the nearest tenth of a foot.

AB = 4.9 ft

Step-by-step explanation:

Here, we are to calculate the length of AB.

Firstly, please check the diagram of the triangle we have in the attachment.

From there we can see that what we are asked to calculate is the length of the hypotenuse(AB) while what we have is the length of the opposite and the angle.

Mathematically, when we have the opposite and the hypotenuse, the trigonometric ratio that links both is the sine

sine = opposite/hypotenuse

Sin 47 = 3.5/hypotenuse

hypotenuse = 3.5/sin 47

hypotenuse = 4.7856

To the nearest tenth of a foot AB = 4.8 ft

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

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