X^2 - 16x + y^2 - 36=0 what is the center of this circle

(8, 18)

Step-by-step explanation:

Complete the square twice:

x^2 - 16x + y^2 - 36 = 0

x^2 - 16x + 8^2 + y^2 - 36 + 18^2 = 0 + 8^2 + 18^2

(x-8)^2 + (y-18)^2 = 388

Center: (8, 18)

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.