Suppose the point (3,1) satisfies the function f(×). what point would satisfy g(x)=-2f(x/2)+1?

(6, -1)

Step-by-step explanation:

Given that point (3,1) satisfies the function f(×).  From the equation

g(x)=-2f(x/2)+1

x/2 = 3

x = 6

Substitute the 1 for f(x/2)

g(x) = -2(1)+1

g(x) = -2 + 1 = -1

The point that would satisfy g(x)=-2f(x/2)+1 is (6, -1)

20

step-by-step explanation:

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

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