Determine the general form of the equation for the circle x^2+ (y + 1)^2 = 2.
x2 + y2 + 2y = 3

x2 + y2 + 2y – 1 = 0

x2 + y2 + y – 1 = 0

x2 + y2 + 2y + 3 = 0

me! what did you put for this question?

step-by-step explanation:

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.

“a term can be a signed number, a variable, or a constant multiplied by a + sign or j sign. in , the terms are 5x , 3y and 8. when a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.” i hope this you.