How much energy would a 15,000 g block of ice need to absorb in order to
melt? The heat of fusion of ice is 333 J/g. Enter your answer to the nearest
whole number of kJ.

The energy a 15,000 g block of ice will absorb in order to melt is 4995 kJ

Step-by-step explanation:

The question relates to the latent heat of fusion of ice, that is the heat absorbed by the solid ice to convert it to liquid water without changing its temperature.

The formula for the energy required to melt the ice is presented as follows;

Energy required = Mass, m × Latent heat of fusion, , of ice

Hence, the mass, m, of the ice = 15,000 g

Latent heat of fusion, , of ice = 333 J/g

Therefore;

Energy required = 15,000 g × 333 J/g = 4995000 J

Hence;

The energy a 15,000 g block of ice will absorb in order to melt = 4995000 J

1000 J = 1 kJ

1 J = 1/1000 kJ

Therefore, 4995000 J = (4995000 J)/(1000 J/kJ) = 4995 kJ.

Which gives;

The energy a 15,000 g block of ice will absorb in order to melt = 4995 kJ.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18