Suppose that 2x^2 - 5x + k = 0 is a quadratic equation with one solution for x. Express k as a common fraction.
Thanks for helping in advance!

if u answer my question i will answer yours

Step-by-step explanation:

2x^2  - 5x  +  k  =   0

If  this has one solution then the discriminant  = 0

So

(-5)^2  - 4 (2) k   = 0

25  - 8k  = 0

25  =  8k

25/8  = k

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)