You have 9 pets:
4 fish,
1 cat,
2 dogs
and 2 birds. What is the probability a pet chosen at random is a dog or a four legged pet?

1/3

Step-by-step explanation:

4 fish, 1 cat,2 dogs,and 2 birds = 9

dogs or 4 legged = cats and dogs = 1+2 = 3

P(dog or 4 legged) = number of dogs or 4 legged / total

                                 =3/9

                                =1/3

⅓

Step-by-step explanation:

Total pets:

4+1+2+2 = 9

Dog or four legged pets: 2 + 1 = 3

Probability: 3/9 = 1/3

square root

step-by-step explanation:

it's 100

step-by-step explanation:

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

  n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the  14th  row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

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