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Suppose point P(4,-9) is translated according to the rule (x, y)→(x+3,y-2). What are the coordinates of P'? Explain.

The coordinates of point P' are (7, -11)

Step-by-step explanation:

we have the rule of the transformation(x,y) —> (x+3, y-2)That means > The transformation is a translation 3 units at right and 2 units downwe know thatTo find out the coordinates of point P' (image of the point P) apply the rule of the translation to the pre-image Pwe haveP(4,-9)soP(4,-9) —> P'(4+3, -9-2)P(4,-9) —> P'(7, -11)thereforeThe coordinates of point P' are (7, -11)

P'= (7,-11)

Step-by-step explanation:

the rule says to add 3 to x, and subtract 2 from y. the 4 in P(4,-9) is x, add 3 to that which will give us the x in the translation, now do the same for y, except with the y rule, -9-2=-11 so P' is (7,-11)

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