(11+i)^2

please help!

121 + 22i - 1

Step-by-step explanation:

Expand:

(11 + i)² = (11 + i)(11 + i)

Note that:

i² = -1

Use FOIL method. Multiply first terms, outside terms, inside terms, then the last two terms:

(11)(11) = 121

(11)(i) = 11i

(i)(11) = 11i

(i)(i) = -1

Combine like terms:

121 + 11i + 11i - 1

121 + (11i + 11i) - 1

121 + 22i - 1

121 + 22i - 1 is your answer.

~

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step-by-step explanation: