Can anyone help me with this please? Thanks again.
In a picture, a man measures 2.3 cm. His actual height is 1.78 m. He is standing beside a flagpole that measures 7.6 cm in the picture. What is the actual height of the flagpole, to the nearest tenth of a meter?

5.88 meters

Step-by-step explanation:

This is a problem of scale factor which uses the concept of ratio.

scale factor is the ratio of length of actual figure to length of its model.

Example: if an architect is drawing design for a building

if height of building is 100 meter but he is drawing this on paper of 1 meter then scale factor will 100/ 1= 100: 1.

It means that for every 100 meter of length of building, it can be represented by 1 meter of its model.

Thus if a building has length 200 meter then its model will be of 200/100 = 2 meter length.

We will solve the given problem based on use of this concept.

Height of man = 1.78 meter

since in picture unit of measure is in cm, lets convert 1.78 meter to centimetre.

1 meter = 100 cm

1.78 meter  = 100* 1.78 cm = 178 cm

height of man in picture = 2.3 cm

Scale factor = actual Height of man/Height of man in picture

              = 178/2.3 = 77391

ratio of actual height of flagpole /  height of flagpole = actual Height of man/Height of man in picture

Substituting the value given in problem we have

actual height of flagpole/7.6 =  178/2.3

=>actual height of flagpole =  (178/2.3)* 7.6 = 588.172 cm.

Thus height of pole is 588.172 cm.

In meter, height of pole is 588.172*100 cm

height of pole is 5.88 meters

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)