Length of rectangle is three times bigger than the width. Area of rectangle is 27. A) find width of rectangle B) find length of rectangle C) find perimeter of rectangle.

What is the answer? I need help to solve it.

Step-by-step explanation:

Let the dimensions of the rectangle be length = L and width = W. Then P = perimeter = 2L + 2W.  A = area of rectangle = L * W.  Finally, L = 3W.

Here A = 27 units^2 = W*(3W) = (3*W^2), or 3W^2 = 27 units^2, or

W^2 = 9 units^2, or W = 3 units.  Then L = 3W = 3(3 units) = 9 units.

The length of the rectangle is 9 units.  See above.

The perimeter of the rectangle is 2(9 units) + 2(3 units) = 24 units.

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).

where is the picture

step-by-step explanation: