The eleventh term from the end of the AP 14, 19, 24, …………., 264 is

Step-by-step explanation:

The sequence given is an arithmetic sequence

14, 19, 24, …………., 264

The nth term of an arithmetic sequence is given as;

Tn = a+(n-1)d where;

a is the first term = 14

d is the common difference = 19-14=24-19 = 5

n is the number of terms = 11(since we are to look for the eleventh term of the sequence)

substituting the given values in the formula given;

T11 = 14+(11-1)*5

T11 = 14+10(5)

T11 = 14+50

T11 = 64

The eleventh term of the sequence is 64

maya’s expression will generate the wrong sum because she violated the commutative property.

step-by-step explanation:

3.73 * 10^7 is the anser for ttm ur welcome < 3

step-by-step explanation: