£ represents a group of 30 people who visited Paris for a weekend break.
A person is chosen at random from the group. What is the probability that this person only visited one of the two places?

17/30

Step-by-step explanation:

We have 30 persons.

13 visited the Eiffel Tower

16 visited the No Tre-Dame Cathedral.

7 did not visit either.

for selecting a person at random, the probability that this person only visited one of the two places is equal to the number of persons that visited only one place divided the total amount of persons.

First, calculate the number of persons that visited only one place.

let's take the initial data and sum it all.

13 + 16 = 29 persons that visited at least one place.

7 persons that not visited any of the places.

29 + 7 = 36

But in the group, we have 30 persons, so here we had a  surplus of 6 persons.

This means that 6 persons visited the two places, so we must discard those 6 in both groups,

People that only visited the Eiffel Tower 13 + 6 = 7

People that only visited the Cathedral 16 - 6 = 10

total: 10 + 7 = 17

proportion = 17/30 = 0.56

Then, the probability that a selected a random person only visited one of the two places is 0.56 or 56%

Hope this helps

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10/60

step-by-step explanation:

if you divide 10 by 60 the answer is 0.166666 while if you divide or solve the other problems it equals 0.6

did you get the answer yet?

step-by-step explanation: