For the system of equations shown below
2x = −y + 6
−4x + 3y = 8
what is the solution to the system of equations?

2x=-y+6
-4x+3y=8
Rewriting the equations;
y+2x=6
3y-4x=8

Multiplying equation I by 3;
3y+6x=18
3y-4x=8
Subtracting equation II from equation I;
10x=10
x=1

Replacing for x in the first equation;
2x=-y+6
2(1)=-y+6
2=-y+6
2-6=-y
-4=-y
y=4

Uneed to add them up 27+18+23=68