Solve this system of equations using any method.

2x – y = 5
4x + y = 7

(2, –4)

(4, –9)

(2, –1)

(4, –3)

(2, –1)

Step-by-step explanation:

Substitution Method

2x – y = 5 and 4x + y = 7 are two given equation

Step 1:

Name the Equation

2x – y = 5 ...(1)

4x + y = 7 ...(2)

Step 2:

From equation (1) we get,

2x = y + 5

x = y + 5/2

Step 3:

Substitute the value of x in equation (2)

i.e.,

4(y + 5/2) + y = 7

2(y + 5) + y = 7

2y + 10 + y = 7

3y = 7 - 10

3y = -3

y = -3/3

y = -1

Step 4:

Now, Substitute the value of y in equation (1)

i.e.,

2x – (-1) = 5

2x + 1 = 5

2x = 5 - 4

2x = 4

x = 4/2

x = 2

VERIFICATION:

2(2) – (-1) = 5 i.e., 4 + 1 = 5

4(2) + (-1) = 7 i.e., 8 - 1 = 7

im alright what do you need

step-by-step explanation:

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)