DAVID G. BARSHELL. SR. SCHOOL SYSTEM
(DAGBASS):
Royal Kids Preparatory (ROPKIP)
Daycare, Elem. Jr. & Sr. High School
Barclay Mission Road, Paynesville, Liberia
Subject: Mathematics
Class: 11th Grade (4th Marking Period Test)
Name:
Date:
Score
Part I: Objectives (4 points each)
Direction: Circle the correct letter that bears the correct answers(NO ERANUS
1. Give 0º =0–90°, solve the value of 0 in cos 0= sin e
a, 30°
b. 60°
c. 45°
d. 90°
2. Solve for x in cos? x +2 = 3
a. 45°
b. 0°
c. 90°
d. 60°
3. In the interval 0º < y < 360°, determine the values of y in 3cos y - 2 = 0
i. 48.2
ii, 228.2°
iii. 311.8°

c. side angle side. u shares the same sides

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

wertyujhgfdcvb

step-by-step explanation: