Which function has real zeros at x = 3 and x = 7?
Of(x) = x2 + 4x – 21
Of(x) = x2 - 4x – 21
O f(x) = x2 – 10x + 21
Of(x) = x2 – 10x – 21

a. 19,958,400

step-by-step explanation:

hope this

did you get the answer yet?

step-by-step explanation:

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct