The load, P (in pounds), that can be safely supported by a horizontal beam varies jointly as the
product of the width, W (in feet), of the beam and the square of the depth, D (in feet), and inversely
as its length, L (in feet). If a beam has a width of 2 feet, a depth of 1 foot and a length of 4 feet, the
load it can support is 10 pounds. How much could the beam hold if the beam had a length of 6
feet, a depth of 2 feet, and a width of 3 feet?

K=? Z=?

10% of increase is the final answer! : )

i can answer this question sweetie!

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c