Suppose that prices of a certain model of a new home are normally distributed with a mean of $150,000. Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

68% of buyers paid between $147,700 and $152,300.

Step-by-step explanation:

We are given that prices of a certain model of a new home are normally distributed with a mean of $150,000.

Use the 68-95-99.7 rule to find the percentage of buyers who paid between $147,700 and $152,300 if the standard deviation is $2300.

Let X = prices of a certain model of a new home

SO, X ~ Normal()

The z score probability distribution for normal distribution is given by;

                             Z  =    ~ N(0,1)

where, = population mean price = $150,000

            = standard deviation = $2,300

Now, according to 68-95-99.7 rule;

Around 68% of the values in a normal distribution lies between and .

Around 95% of the values occur between and .

Around 99.7% of the values occur between and .

So, firstly we will find the z scores for both the values given;

         Z  =    =    = -1

         Z  =    =    = 1

This indicates that we are in the category of between and .

SO, this represents that percentage of buyers who paid between $147,700 and $152,300 is 68%.

step-by-step explanation:

one day the were 5 ducks, and their king told them to multiply their kingdom. so each went their own seperate way and met 4 other ducks on their journey.

when the ducks returned to their kingdom, it was discovered that there were 5 groups of 5 ducks. when the kind counted the number of ducks in total (including the ones he sent out earlier) he counted 25.

therefore 5 times 5 is 25.

the end. : )

answer: need a picture

step-by-step explanation: