What is the volume, in cubic millimeters, of the composite figure? (Round to the nearest hundredth. Use 3.14 for Pi.)V cylinder = pi r squared h. V sphere = four-thirds pi r cubed.

A cylinder and half sphere. Both have a radius of 4 millimeters. The cylinder has a height of 6 millimeters.

Volume of composite is 320.28mm³

Step-by-step explanation:

This problem bothers on the mensuration of solid shapes, cylinder and sphere,

to solve the volume of the composite figure

1.Let us solve for the volume of the cylinder

V= πr²h

Given radius r= 4mm

Height h= 6mm

V= 3.14*(4)²*6

V=3.14*16*6

V= 301.44mm³

2. Let us solve for the volume of sphere

V= 4/3πr³

V= 4/3*3.14(4)³

V= 4/3*3.14*9

V= 113.04/3

V= 37.68mm³

But the sphere is half

So V= 37.68/2

V= 18.84mm³

Hence composite volume is

18.84+301.44

Volume = 320.28mm³

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.