What percentage of Coach passengers did not check bags

35.2%

Step-by-step explanation:

Add all of the passengers up for the total.

10 + 81 + 14 + 57 = 162

The fraction for how many Coach passengers that did not check their bags is:

57/162

Simplify to a decimal and multiply by 100 to get percent.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

50.6

step-by-step explanation: