A flexible wire is bent into a semicircular arc. The length of AB is 18 meters. Find the length of the wire. Use 3.14 as an approximation for π .

28.26 meters

Step-by-step explanation:

Hi, to answer this question we have to find the perimeter of the semicircle.

P = (2 π r ) /2 (perimeter of a circle divided by 2)

The length of AB is the diameter of the circle (18 meters)

Since

Diameter (d) = 2 radius (r)

Replacing with the value given:

18 =2r

18/2=r

9 =r

Back on the perimeter formula

P = (2 π r ) /2

Replacing with the values given

P = (2 x 3.14 x 9) /2

P = 28.26 meters