1.Write the expression for when you translate the graph of y = x + 7 one unit to the left

2. Write the expression for when you translate the graph of y = 3x− 5 one unit to the right.

1) x<-6

2) x>2

Step-by-step explanation:

The expression that translate the graph of y = x + 7 one unit to the left is am inequality expressed as:

y<1

= x+7<1

Moving 7 to the other side we have:

x < 1-7

x< -6(This gives the required expression.

2) The expression that translate the graph of y = 3x− 5 one unit to the right is expressed as 3x-5>1

On simplifying:

Taking 5 to the other side we have;

3x>1+5

3x>6

Dividing both sides by 3 will give:

3x/3>6/3

x>2 (This gives the required expression

true? is that what you're asking or do you mean something else?

the expected value of the random variable : 0, 1 and 2

step-by-step explanation: