Two buildings are 35 feet apart. The angle of elevation from the top of the smaller building to the top of the taller building is 42˚. The smaller building is 32 feet high. Find the height of the taller building.

Height of the taller building is 63.5ft

Step-by-step explanation:

Kindly find attached rough sketch of the problem for your reference.

Let the small building be A and the taller building be B

From the sketch the two buildings form a right angle triangle

We can solve for x which is the height of the taller building relative to the small building using

SOH CAH TOA

Applying TOA we have

Tan θ= opposite/adjacent

Tan 42°= x/35

x= Tan 42*35

x= 0.9*35

x= 31.5ft

Hence the height of the taller building is = x+height of small building = 31.5+32= 63.5ft

sorry man i accidentally pressed yes my bad

step-by-step explanation:

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!