Mary has been offered two jobs. Job a has a starting salary of 36,000 and a raise of 1500 every year. Job B has a starting salary of 29,000 and a raise of 2500 every year .In how many years would Mary’s salary be the same at both companies .What would that salary be?

Number of year Mary’s salary be the same at both = 7 year

Equal salary amount =  46,500

Step-by-step explanation:

Given:

Starting salary in job A = 36,000

Gain per year in job A = 1,500

Starting salary in job B = 29,000

Gain per year in job B = 2,500

Find:

Number of year Mary’s salary be the same at both = ?

Equal salary amount = ?

Computation:

Assume : in x year salary from job A is equal to salary from job B

Salary from job A in x year = 36,000 + 1,500 x Eq1

Salary from job B in x year = 29,000 + 2,500 x Eq2

From Eq1 and Eq2

36,000 + 1,500 x = 29,000 + 2,500 x

7,000 = 1,000 x

x = 7 Year

Number of year Mary’s salary be the same at both = 7 year

From Eq1

Equal salary amount =  36,000 + 1,500(7)

Equal salary amount =  36,000 + 10,500

Equal salary amount =  46,500

answer: 48

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