Quadrilateral problems on the coordinate plane
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle:
A(-7,-5), B(-7,6), C(-4,6), and D(-4,-5).
Given these coordinates, what is the length of side CD of this rectangle?

answear:

a

step-by-step explanation: a

answer: h

step-by-step explanation:

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²