Matt and Taylor are taking a test. The test is designed to produce an overall mean score of 80, with a standard deviation of 6 for all test takers. Suppose Matt scored an 85 on the test and Taylor scored a 78 on the test. Given that the data is approximately normal, find the probability that another test taker, chosen at random, scored less than Matt and more than Taylor.

P (r) = 1/3

Step-by-step explanation:

Matt  85 - 80 = +(5)

Taylor 80-78 = - (2)

+5-2 = 3 rise so deviation is the same.

Another test taker in 4 outcomes less than taylor more than taylor less than matt more than matt, would also be the same as AnB union.

So their are 3 outcomes = 1/3 = 0.333 rep.

7 ft 6 in means 7 1/2, because 6 in is 1/2 of a foot. 7 ft 8 in means 7 2/3 because 8 in is 2/3 of a foot. 23/3 = 7 2/3. 15/2 = 7 1/2.

23/3   *   15/2   = 57 1/2

step-by-step explanation: