Alex needs to report his bowling average for the school newspaper. Here are his scores from the last 20 games: 132, 141, 110, 96, 154, 135, 111, 139, 102, 135, 133, 127, 99, 124, 129, 201, 131, 128, 134, and 135. Part A: What are the mean and median of this data? Part B: Which one of those two measures of central tendencies should he use for the newspaper and why? Part C: Are there any outliers? Please answer ASAP

Part A:

Mean: 129.8

Median: 131.5

Step-by-step explanation:

The mean is the average so we add everything together and then divide it by however many numbers there are. 132 + 141 + 110 + 96 + 154 + 135 + 111 + 139 + 102 + 135 + 133 + 127 + 99 + 124 + 129 + 201 + 131 + 128 + 134 + 135 = 129.8

The median is the number in the middle. That is the number in between the rest from smallest to largest. 96, 99, 102, 110, 111, 124, 127, 128, 129, 131, 132, 133, 134, 135, 135, 135, 139, 141, 154, and 201

The medians are 131 and 132 so we add them together then divide by 2. That gives is 131.5 so that is our answer. I hope this helps and please mark me brainliest!

no idea

step-by-step explanation:

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.