It takes 12.5 mL of a 0.30 M HCl solution to neutralize 285 mL of NaOH solution.

What is the Molarity concentration of the NaOH solution?

13.15 M NaOH

1.5 M NaOH

0.15 M NaOH

0.013 M NaOH

The molarity concentration of the NaOH solution is 0.013M NaOH

The equation of reaction is given as:

Concentration of Hcl,

Volume of Hcl,

Concentration of NaOH =

Volume of NaOH,

From the equation of reaction:

Number of moles of Hcl,

Number of moles of NaOH,

The formula for neutralization is given as:

Substitute the values of the parameters

The molarity concentration of the NaOH solution is 0.013M NaOH

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0.013 M NaOH

Step-by-step explanation:

HCL + NaOH = NaCL + water

The mole ratio of acid and base is 1:1

Molarity is equal to the moles of solute divided by the liters of solution

Solute mole = 12.5 × 10^-3 × 0.3

= 0.003075

To neutralize 0.00375mol of HCl, 0.00375 mol of NaOH will be required. Since molarity is moles per liter, divide this amount of moles by the volume in liters:

Molarity = 0.00375/285 × 10^-3

Molarity = 0.0131 M

inequality:

620-37.4p ≥ 450

the minimum amount of packages needed to be removed from the elevator is 5.

step-by-step explanation: