What is the maximum height for -16t^2+96t+63

h(3) =  207 feet

Step-by-step explanation:

what is the maximum height for -16t^2+96t+63

h(t) = -16t^2+96t+63

We see  max height at the vertex of this parabolic function

x = -96/2*(-16)  = 3 seconds

h(3) = -16*3*3  + 96*3  + 63

h(3) =  -144  + 288 + 63

h(3) =  207 feet

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

a

step-by-step explanation:

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