For a normal distribution given a standard deviation of 3.8 in a mean of 54 what percent lies above 48
A 0.1690
B 0.0571
C 0.7660
D 0.9429

choice D.) 0.9429

Step-by-step explanation:

Given a Normal data set

mean u = 54

standard deviation s = 3.8

we want P( X > 48)

Standardize this probability so we can use Z-scores.

P( X > 48) = P( (X - u)/s > (48 - 54)/3.8 ) = P(Z >  -1.5789)

so  I look for P ( Z > 1.5789) = 0.0571

so  P(Z > -1.5789) = 1 - P(Z > 1.5789) = 1 - 0.0571 = 0.9429

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation: