What is the distance between the points (1.6,0.1) and (2.4,1.6)?

1.7 units

Step-by-step explanation:

Let (1.6,0.1) be (x1,y1) and (2.4,1.6) be (x2,y2)

By using distance formula,

d= sqrt (x2-x1)^2 + (y2-y1)^2

=sqrt (2.4-1.6)^2 + (1.6-0.1)^2

=sqrt (0.8)^2 + (1.5)^2

=sqrt 0.64+2.25

=sqrt 2.89

=sqrt (1.7)^2

=1.7

Therefore,the distance between them is 1.7 units

2

step-by-step explanation:

should have been evaluated with one odd value and one even value. the expressions have equivalent values when . when , the first expression has a value of 3 and the second

step-by-step explanation: