During his 2009 MVP season for the St. Louis Cardinals, Albert Pujols hit 93
singles, 45 doubles, 1 triple, and 47 home runs in a total of 568 at bats. The
following table arranges these data in terms of the number of bases for a hit,
counting O bases for the times when he did not get a hit and 4 bases for
home runs.
Number of
Bases
0
1
3
4
2
451
Number of
Times
382
47
To the nearest thousandth, what was E(X), the expected number of bases for
Albert Pujols in a typical at bat in 2009?
O
A. 0.327
OB. 0.487
O
C. 0.658
OD. 0.597

E(Bases ) = 0.6584499955929  choice C.

Step-by-step explanation:

We want Expected number of bases during 2009

E(bases) = SUM (number of outcomes) *probabiility of outcome

93 + 45 + 1 + 47   = 176 hits

but there are a total of 568 bats

568 - 176 =   392 misses?

E(Bases) =  0* P( miss) + 1 *  P( hitting singles) + 2*P(hitting doubles) + 3*P(hitting triples) + 4*P(home run)

E(Bases) =  0 + 93/568 +  2* (45/568) + 3*(1/568) + 4*(47/568)

0.16373239  + 0.158450 + 0.0052816901 + 0.33098591549

E(Bases ) = 0.6584499955929

this is not the answer this is just a question. is this middle school math?

step-by-step explanation: