An equilateral triangle has a base of 44 meters and a height of h meters. Inside that triangle is constructed a second equilateral triangle of base 22 meters and a height
of 0.5h meters. Inside the second triangle is constructed a third equilateral triangle of base 11 meters and a height of 0.25h meters.
What percent of the area of the largest triangle is the area of the smallest triangle?
% of the area of the largest triangle.
The area of the smallest triangle is
(Type an integer or a decimal)

6.25 %  of area of Large triangle =  area of smallest triangle

Step-by-step explanation:

Area of large triangle L = (1/2)*base*height

L = (1/2)*(44 m)* h

L = 22*h  square m.

2nd equilateral triangle area:  S =(1/2)*(22 m)*(0.5h)

S = 5.5*h sq. m.

3rd smallest equilateral triangle area : T = (1/2)*(11 m)*(0.25h)

T = 1.375*h sq. m

Find percent P  where  T = P* L,     1.375*h = P * 22*h

P = 6.25%  = 0.0625

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.