The center of a circle is located at (3, -4). The radius of the circle is 6.

What is the equation of the circle in general form?

x2 + y2 + 6x − 8y − 11 = 0
x2 + y2 − 6x + 8y − 11 = 0
x2 + y2 + 6x − 8y + 19 = 0

B

Step-by-step explanation:

The equation of a circle in standard form is , where (h, k) is the center and r is the radius. The general form is simply the expanded form of the standard. Let's first write the standard form.

Here, the center is (3, -4) and the radius is r = 6, so:

Now expand:

x² - 6x + 9 + y² + 8y + 16 = 36

x² + y² - 6x + 8y - 11 = 0

The answer is B.

x² + y² - 6x + 8y - 11 = 0

Step-by-step explanation:

Equation of a circle:

(x - h)² + (y - k)² = r²

(x - 3)² + (y + 4)² = 6²

x² - 6x + 9 + y² + 8y + 16 = 36

x² + y² - 6x + 8y - 11 = 0

-14

step-by-step explanation:

2x2 – 2(x+4)

=2x2-2（5+4）

=4-2×9

=4-18

=-14

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: