Suppose that Adam rolls a fair six-sided die and a fair four-sided die simultaneously. Let AAA be the event that the six-sided die is an even number and BBB be the event that the four-sided die is an odd number. Using the sample space of possible outcomes below, answer each of the following questions. What is P(A)P(A)P, (, A, ), the probability that the six-sided die is an even num

0.5

Step-by-step explanation:

The sample space of a fair six-sided die and a fair four-sided die rolled simultaneously is given below:

where in each pair (x,y), x represents the four-sided die and y represents the six sided die.

Total Number of Possible Outcomes =24

Event A is the event that the six-sided die is an even number.

n(A)=12

Therefore, the probability that the six-sided die is an even number:

P(A)=12/24=0.5

idk

step-by-step explanation: i just don't

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: