What is the equation of a line with a slope 4/5 through (-15,5)

You can find the slope-intercept equation of a line by plugging the slope and one coordinate pair into the point-slope form, y - y_1 = m (x - x_1). M will be slope and y_1 and x_1 will be the coordinate pair.

y - y_1 = m (x - x_1)      Plug in the values
   y - 5 = 4/5 (x - (-15)   Cancel out the double negative
   y - 5 = 4/5 (x + 15)    Use the Distributive Property
   y - 5 = 4/5x + 60/5  Simplify the fraction
   y - 5 = 4/5x + 12      Add 5 to both sides
        y = 4/5x + 17
 

Ithink it is 52