5. At the local burger joint, 45% of the customers purchase cheeseburgers and 80% purchase fries. If a customer is selected at randomlet the event that they bought a burger be A and the event that they purchased fries be B. If A and B are independent what is P(A or B)?

P (A or B) =  0.53

Step-by-step explanation:

P(A or B) is the probability where one of the events happened but not both of them.

Probability of event A = 0.45

Probability of not event A = 1 - 0.45 = 0.55

Probabiity of event B = 0.80

Probability of not event B = 1 - 0.80 = 0.20

Then, the probability that one customer buys a burger but does not buy fries is:

P1 = 0.45*0.20 = 0.09

Probability of purchasing fries but not a burger:

P2 = 0.80*0.55 = 0.44

P (A or B) = P1 + P2 = 0.09 + 0.44 = 0.53

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )