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Mathematics, 05.05.2020 07:39 jaystitt1152683

X1 βˆ’ x2 + x3 = 6

2x1 βˆ’ x2 + x3 = 5

3x1 + x2 + 3x3 = βˆ’20

x1 = x2 = x3 =

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Answers: 3

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You know the right answer?
X1 βˆ’ x2 + x3 = 6

2x1 βˆ’ x2 + x3 = 5

3x1 + x2 + 3x3 = βˆ’20

x1 = x2...
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