Find the square (2m - 8)^2

(2m -8)^2 = (2m-8)(2m-8)

(2m-8)(2m-8)

2m x 2m = 4m^2

2m x -8= -16m

-8 x 2m= -16m

-8 x -8 = 64

4m^2 -16m -16m + 64

4m^2 -32m + 64

Square: 4m^2 -32m + 64

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752

the answer is a if my teacher taught me correct