A grab bag contains 9 nasty teeth and 6 spinners.
Bill is the first to select from the grab bag and then
Jane selects from the remaining gifts in the grab bag.
What is the probability that Bill selects one of the nasty teeth
and then Jane selects a spinner?
(Express your answer as a percent rounded to the nearest whole number)

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

answer: 5 17/33 % (to the tenth)

step-by-step explanation:

he guessed: 34.5 pounds

actual weight is 32.7

there for he is off:

34.5 -32.7 = 1.8

32.7 is the 100%

1.8 represents %? of 32.7

therefore:

32.7   - 100%

1.8     -     x%

x= 1.8*100%/32.7% = 18*100%/327%

x=1800%/327%   = (5 165/327)%

to the tenth:

5 17/33 %

2/3=10/15

1/5=3/15

10+3=13/15

2 13/15 is the answer