A television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. For this to happen, it will have to move one of its most viewed shows to another slot. The network conducts a survey asking its viewers which show they would rather watch. The network will keep its current lineup of shows unless the majority of the customers want to watch the new show. The network receives 827 responses, of which 428 indicate that they would like to see the new show in the lineup.

Select the hypotheses to test if the television network should give its newest television show a spot during prime viewing time at night. A. H0: p = 0.50; HA: p = 0.50B. H0: p ? 0.50; HA: p < 0.50C. H0: p ? 0.50; HA: p > 0.50

H0: p ≤ 0.50; HA: p > 0.50

The null hypothesis is that the majority of the customers would not want to watch the new show.

H0: p ≤ 0.50

The alternative hypothesis is that the majority of the customers would want to watch the new show.

HA: p > 0.50

Note : majority means greater than 50% (p > 0.50)

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

The null hypothesis is that the majority of the customers would not want to watch the new show, so they maintain the original lineup.

H0: p ≤ 0.50

The alternative hypothesis is that the majority of the customers would want to watch the new show. So they alter the original lineup of programs.

HA: p > 0.50

Note : majority means greater than 50% (p > 0.50)

d

step-by-step explanation:

3-4

step-by-step explanation:

the answer is 3-4 because both 45 and 60 has a multiple of 15.

45/3=15

60/4=15

therefore the odds against selecting a red is 4-3