If h(x)=6-x what is the value of (h•h)(110)

The given function : h(x) = 6 - x

We know that for any functions f(x) and g(x)

f*g (x)=f(x)\times g(x)

Therefore , h*h (x)=h(x)\times h(x)

h*h (x)=(6-x)(6-x)=(6-x)^2

h*h (x)=(6)^2-2(6)(x)+x^2 [ Using identity   (a-b)^2=a^2+2ab+b^2 ]

h*h (x)=36-12(x)+x^2

\>\ h*h (x)=36-12(x)+x^2 Now, at x= 10 , we get

h*h (10)=36-12(10)+(10)^2

h*h (10)=36-120+100=36+100-120=136-120=16

Hence, the value of (h*h)(10) = 16

hoped it helped

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step-by-step explanation:

94

step-by-step explanation:

average the numbers and use a variable to figure out the minimum to get a 90.

(79+94+91+92+x)/5=90

x = 94