Sheila and Lenore were driving to their grandmother’s house. Lenore left 1 hour after Sheila. Sheila drove at a rate of 45mph, and Lenore drove at a rate of 60mph. How long will it take for Lenore to catch up to Sheila?

It'll take 3 h before Lenore catch up to Sheila.

Step-by-step explanation:

To solve this problem we first need to calculate the relative speed between the two. Since they're going at the same direction we need to subtract their individual speeds if their directions were oposite we would have to sum their speeds. In this case we have:

relative speed = Lenore speed - Sheila speed

relative speed = 60 - 45 = 15 mph

Since Sheila left 1 h before Lenore and she drove at a rate of 45 mph, then she had covered a distance of:

distance = time*speed = 1*45 = 45 miles

Before Lenore left, so in order for Lenore to catch up to Sheila she needs to cover that distance at a relative speed of 15 mph.

time = distance/(relative speed) = 45/15 = 3 h

It'll take 3 h before Lenore catch up to Sheila.

option a.

step-by-step explanation:

if you look closely at the graph, we can notice that the function is not defined at two different points.

if you look at functions b and c, you will notice that both functions are not defined at just one point. the function b is not defined at x= -5/2 and function c is not defined at x=-5. both options are discarded, given that our function should not be defined at two fiferent points.

now, if you look closely at the graph you will notice that the function sketched is not defined at x=5 and x=-2.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐