Henry is asked to find the exact value of cosine StartFraction 10 pi Over 3 EndFraction. His steps are shown below. 1. Subtract 2 pi from StartFraction 10 pi Over 3 EndFraction as many times as possible: StartFraction 10 pi Over 3 EndFraction – 2 pi = StartFraction 4 pi Over 3 EndFraction 2. Find the reference angle for StartFraction 4 pi Over 3 EndFraction: StartFraction 3 pi Over 2 EndFraction – StartFraction 4 pi Over 3 EndFraction= StartFraction pi Over 6 EndFraction. 3. The cosine value for StartFraction pi Over 6 EndFraction is StartFraction StartRoot 3 EndRoot Over 2 EndFraction. 4. The cosine value is positive because StartFraction pi Over 6 EndFraction is in the first quadrant. Which of the following describes Henry’s errors?