Find the equation of the line that is perpendicular to y=-2/3x and contains the point (4,-8)

y = 3/2x -14

Step-by-step explanation:

y = -2/3 x

has a slope of -2/3

We want a line perpendicular

Take the negative reciprocal to find the slope

- (1 / -2/3)

3/2

The slope of a line perpendicular is 3/2

Using the slope intercept form of a line

y = mx+b  where m is the slope and b is the y intercept

y = 3/2x +b

Substitute a point into the equation

-8 = 3/2(4) +b

-8= 6+b

Subtract 6 from each side

-8-6 = b

y = 3/2x -14

w'x is 0.

hope it