A 2-column table with 6 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2, 3. The second column is labeled f of x with entries negative 10, negative 8, negative 6, negative 4, negative 2, 0. Which is an x-intercept of the continuous function in the table?

An x-intercept of the continuous function in the table is at (f(x) = 0) that is (x = 3) is the x-intercept of the continuous function given in the table and this can be determined by observing the table.

Given :

x                   f(x)

-2                  -10

-1                    -8

0                   -6

1                    -4

2                   -2

3                    0  

An x-intercept of the continuous function in the table is at (f(x) = 0) that is (x = 3) is the x-intercept of the continuous function given in the table.

An y-intercept of the continuous function in the table is at (x = 0) that is (f(x) = -6) is the y-intercept of the continuous function given in the table.

For more information, refer to the link given below:

link

Step-by-step explanation:

Given the table

..xy=f(x)

-2-10

-1-8

0-6

1-4

2-2

30

x intercept means that the value of x when y = f(x) = 0, it is the point where the graph pass through or cut the x axis

So, from the diagram, it is the last column,

F(x) = 0, then, x=3

Then, the x intercept is 3

Extra

Also, for y intercept, it is the point when x = 0 for this case the y intercept is -6/

lol

step-by-step explanation:

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2